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-3x^2-11x+2=0
a = -3; b = -11; c = +2;
Δ = b2-4ac
Δ = -112-4·(-3)·2
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{145}}{2*-3}=\frac{11-\sqrt{145}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{145}}{2*-3}=\frac{11+\sqrt{145}}{-6} $
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